a-cosmology-group/acg#337

One would have to show some derivation how to get this equation. Especially if Maxwell is referred.

$π^{21}$

seems like an absurd inclusion.

Hi Francois. The best way to do this sort of science is to let stand until disproven. If it cannot be disproven over a long period of time, then it will be a fundamental truth of nature. It’s interesting to look at Wikipedia’s “Hubble’s Law” page, where the “ballpark” measured values of Hubble’s Constant are displayed on charts. Notice how this equation effectively solves the Hubble tension issue. Kind regards, David Hine.

This is easily disproved by calculating it:

$$ \frac{2 \times (1 \mbox{ Mpc}) \times c}{\pi^{21}} = \frac{2 \times (1 \mbox{ Mpc}) \times (299792 \mbox{ km/s})}{2.75516\times 10^{10}} = 2.176\times 10^{-5} \frac{\mbox{ Mpc \ km}}{\mbox{s}} \ne 70.94 \frac{\mbox{km}}{\mbox{s \ Mpc}} $$

The units don’t match, ∴ it is disproved.

The previous post is changing the structure of basic maths proceedure, complicating it, and introducing errors. The best way is to do this calculation is directly on an online calculator, inputing the equation units EXACTLY as stated previously to give each individual Megaparsec unit of spacetime its “additional acceleration contribution” value of 70.94 k/s/Mpc. Kind regards, David Hine.

The error is introduced after the second = sign, where the challenger separates the seconds, and places them as a denominator. From then on it all falls apart because maths rules have been breached. It must be remembered that the original denominator of Pi to the power of 21 in the original equation MAINTAINS the correctness of the equation. We must NEVER forget we are dealing with the “spacetime” background here. It’s a difficult concept to picture, (like Relativity), it works for the purpose of “fixing” Hubble’s Constant at 70.94 k/s/Mpc. Regards, David Hine.

Hi. It will be apparent that “local” variations of Ho will occur, if there is a large nearby galaxy, or if a particulare area of the cosmos is sparcely poulated (a void). Local galaxies and voids will also affect light speed either way, as seen as a local Doppler shift variation. This Hubble equation ties together Ho and C, so if light speed in a certain locality goes either up or down, so will Ho accordingly.

With very kind regards, David Hine.

Hi,

This Hubble equation dirctly connects C to Ho numerically.

So, in some regions of the cosmos near a huge galaxy, blackhole (Hawking), or a void region, light

speed C and Ho will be slightly changed, giving rise to the observed Hubble Tension.

Also (because Ho is unafected by the age of the universe), the reciprocal of Ho at 13.8 billion light

years is the “Hubble Horizon Distance” only.

With kind regards, David Hine——–Beam me up!!

Hi.

First appearing in 2008, and later online in 2017,

the Hubble (Ho) calculating equation:-

   **2 x oneMpc x C, divided by Pi to the power of 21 = 70.94 k/s/Mpc**

now becomes more applicable, as it now plays a part in studying the “Hubble Tension” issue.

Hubble Tension is due to the “local” effect of large gaxaxies, voids and blackholes on “C” (Hawking)

in the particular “space region localities” of where the Hubble (Ho) readings are focused.

With kind regards, David Hine………..Beam me up !!!!!!!!!!!

Hi,

There was a quote by Einstein when his work was under attack, saying he did not wish to get “drawn into”

a “stone circle of constant attacks, in order to confuse and derail him” by those that did not want to,

or were unable to understand the extremely unfamiliar concepts described by his equations and

the unconventional maths procedures that had to be deployed in the process..

Einstein concluded by saying to properly test his work, use various observations from the astronomers.

Special Relativity was finally proven fact observing the orbits of planet Mercury.

Here, the place to watch is Wikipedia’s “Hubbles Law” page, especially the charts displaying the values

of the incoming Ho measurements, and also how the new Hubble Tension issue pans out.

That’s how it is, and those Wikipedia charts will either prove or disprove this equation.

Eventually, the Ho value of 70.94, (where C is 299792.458 k/s) will need to be displayed on Wikipedia.

With very kind regards, David Hine……………Beam me up !!!

Hi,

What do you think Stephen Hawking would have made of the Ho calculating equation :-

              2 x oneMpc x C, divided by Pi to the power of 21 = 70.94 k/s/Mpc     ?

In this case, would Stephen have prefered to link Ho more strongly with distance or with C or with black holes?

            David Hine....................Beam me up !!

Hi.

The implications of this equation are to directly link Ho to C numerically, and so provide a much more

precise “ballpark” Ho to assist the study and causes of the “Hubble Tension” issue that’s really confusing

theoretical cosmologists today..

Long before the Hubble Tension was ever observed, the equation serves (and still does) to show the

age of the universe is not directly linked to Ho.

These are the main functions of this Ho equation to date.

There are further interesting cosmology implications from this Ho equation that will be discussed later..

Best regards to all, David Hine………….Beam me up !!!!!!!!!